12t^2+16t-60t=0

Solution for 12t^2+16t-60t=0 equation:

12t^2+16t-60t=0

We add all the numbers together, and all the variables

12t^2-44t=0

a = 12; b = -44; c = 0;
Δ = b2-4ac
Δ = -442-4·12·0
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-44}{2*12}=\frac{0}{24}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+44}{2*12}=\frac{88}{24}
=3+2/3
$